Asked by Aa

Find the points on y=(-x^2+4x-3)^3 that has a horizontal tangent line.
Answered by Steve
y' = 3(-x^2+4x-3)^2 (-2x+4)
y'=0 when x = 1,2,3
so, the tangent is horizontal at

(1,0),(2,1),(3,0)
Answered by Aa
Tnx! :D
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