Asked by Anonymous
Ethan has $120 more than Dilton. After Ethan spent 80% of his money and Dilton spent 60% of his money, they still have $270 left altogether. How much money does Ethan have left in the end?
Answers
Answered by
mathhelper
Dilton's amount --- x
Ethan's amount ---- x+120
amount left after the spending spree:
Ethan: 0.2(x+120)
Dilton: .4x
.4x + .2(x+120) = 270
.4x + .2x + 24 = 270
calculate the rest and state you conclusion
Ethan's amount ---- x+120
amount left after the spending spree:
Ethan: 0.2(x+120)
Dilton: .4x
.4x + .2(x+120) = 270
.4x + .2x + 24 = 270
calculate the rest and state you conclusion
Answered by
Bosnian
E = Ethan's money in beginning
D = Dilton's money in beginning
Ethan has $120 more than Dilton means:
E = D + 120
After Ethan spent 80% of the money he got 20% of the money.
20% = 20/100 = 0.2
Ethan has 0.2 ( D + 120 ) money left
After Dilton spent 60% of the money, he got 40% of the money.
40% = 40 / 100 = 0.4
Dilton has 0.4 D of money left.
In total they have left:
0.2 ( D + 120 ) + 0.4 D = 270
0.2 D + 24 + 0.4 D = 270
0.6 D + 24 = 270
Subtract 24 to moth sides
0.6 D = 246
D = 246 / 0.6 = 410
Dilton have $410 in beginning
E = D + 120
E = $410 + $120 = $530 in beginning
After Ethan spent 80% of the money he got 20% of the money.
20% = 20 / 100 = 0.2
In the end Ethan have left 0.2 ∙ $530 = $106
D = Dilton's money in beginning
Ethan has $120 more than Dilton means:
E = D + 120
After Ethan spent 80% of the money he got 20% of the money.
20% = 20/100 = 0.2
Ethan has 0.2 ( D + 120 ) money left
After Dilton spent 60% of the money, he got 40% of the money.
40% = 40 / 100 = 0.4
Dilton has 0.4 D of money left.
In total they have left:
0.2 ( D + 120 ) + 0.4 D = 270
0.2 D + 24 + 0.4 D = 270
0.6 D + 24 = 270
Subtract 24 to moth sides
0.6 D = 246
D = 246 / 0.6 = 410
Dilton have $410 in beginning
E = D + 120
E = $410 + $120 = $530 in beginning
After Ethan spent 80% of the money he got 20% of the money.
20% = 20 / 100 = 0.2
In the end Ethan have left 0.2 ∙ $530 = $106
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