Asked by Wheeler
log5(x)-log5(x+4)=-1 (the 5s are in the base of the log)
I need to find x
I know you can combine them into log5(x/x+4)= -1 but i don't know what to do from there
I need to find x
I know you can combine them into log5(x/x+4)= -1 but i don't know what to do from there
Answers
Answered by
mathhelper
log5(x)-log5(x+4)=-1
log5[ x/(x+4) ] = -1
now use your definition of logs
x/(x+4) = 5^-1 = 1/5
5x = x+4
4x = 4
x = 1
check:
LS = log<sub>5</sub> (1) - log<sub>5</sub> (5)
= 0 - 1
= -1
= RS
log5[ x/(x+4) ] = -1
now use your definition of logs
x/(x+4) = 5^-1 = 1/5
5x = x+4
4x = 4
x = 1
check:
LS = log<sub>5</sub> (1) - log<sub>5</sub> (5)
= 0 - 1
= -1
= RS
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