Asked by momen
A small bicycle pump is filled with helium (He) gas. With constant
pressure, the gas is forced out through a small aperture in two
seconds. The same pump is filled with hydrogen bromide (HBr) gas.
Using the same pressure, how long will it take to force out this gas?
pressure, the gas is forced out through a small aperture in two
seconds. The same pump is filled with hydrogen bromide (HBr) gas.
Using the same pressure, how long will it take to force out this gas?
Answers
Answered by
DrBob222
Using the same pressure and the same tire we know the volume for He is the same as the volume for HBr gas. Use Graham's Law. Let's use a volume of 2 L.
So rate for He is 1 L/2 sec = 0.5 L/s. rate HBr = 1 L/seconds. I've let mm stand for molar mass. Then
(rate He/rate HBr) = sqrt (mm HBr/mm He)
Substitute the numbers and solve. Post your work if you get stuck.
So rate for He is 1 L/2 sec = 0.5 L/s. rate HBr = 1 L/seconds. I've let mm stand for molar mass. Then
(rate He/rate HBr) = sqrt (mm HBr/mm He)
Substitute the numbers and solve. Post your work if you get stuck.
Answered by
Anonymous
9 second