Asked by Ana
A bicycle pump contains 250 cm3 of air at a pressure of 90 KPa. If the air is compressed, the volume is reduced to 200 cm3. What is the pressure of the air inside the pump?
use p1v1 = p2v2
V1 = 90 and V2 =
P1= 250 cm and p9= 200
P1V1 = p2V2
V2=p1V1/p2
V2=250cm3x90kpa/200cm3 =
V2=
use p1v1 = p2v2
V1 = 90 and V2 =
P1= 250 cm and p9= 200
P1V1 = p2V2
V2=p1V1/p2
V2=250cm3x90kpa/200cm3 =
V2=
Answers
Answered by
DrBob222
You need to read the problem again.
V1 = 250 cc
V2 = 200 cc
P1 = 90 kPa
P2 = ?
V1 = 250 cc
V2 = 200 cc
P1 = 90 kPa
P2 = ?
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