Question

If the probability that the Islanders will beat the Rangers in a game is 85%, what is the probability that the Islanders will win exactly three out of five games in a series against the Rangers? Round your answer to the nearest thousandth.

Answer 1

3(.85) + 2(.15) = ?

Answer 2

Repeating your post will not get you any faster or better responses.

Answer 3

the other response was wrong

Answer 4

I did it down below using binomial logic

Answer 5

PsyDAG - C(n,r) p^r q^(n-r)

Answer 6

see my solution

Answer 7

Please everybody Google binomial probability distribution.

Answer 8

for example (I can not postlink)

......The Binomial Probability distribution of exactly x successes from n number of trials is given by the below formula- P (X) = nCx px qn - x Where, n = Total number of trials x = Total number of successful trials p = probability of success in a single trial q = probability of failure in a single trial = 1-p Solved Examples For Binomial ProbabilityThe Binomial Probability distribution of exactly x successes from n number of trials is given by the below formula- P (X) = nCx px qn - x Where, n = Total number of trials x = Total number of successful trials p = probability of success in a single trial q = probability of failure in a single trial = 1-p Solved Examples For Binomial Probability
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ps
we would write p^x q^(n-x)

Answer 9

Daniela's problem is NOT a clear-cut case of the Binomial Distribution.

To win 3 out of 5 games in a 5 game series we can't
just do C(5,3)(.85^3)(.15)^2
since that would include such cases as WWLWL, which among
others have to be excluded, since the series was already won after
the third W.
I explained it all in my post here.

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Answer 10

But she did not say the series stopped after three wins as it would in some real life situations. The implication as I understood it was they were playing all five.

Answer 11

In any best of 5-game series, as soon as you win 3, you won the series.
So to actually play 5 games, a situation such as WWLWL would not exist
even though it would be in the set of C(5,3)
So instead of 10 cases in the C(5,3) you only have 6 such games
The first 4 games must be permutations of WWLL, which is 4!/(2!2!) or 6

Answer 12

I understand what you are saying and agree in a real athletic event. However it is not clear to me that ending after three wins was what the problem writer had in mind. Anyway I apologize or freaking out about it.