Asked by Anonymous
A store owner had coconuts and papayas. The ratio of coconuts to papayas was 5:2. After 1/2 of the coconuts and 18 papayas were sold, there were 2 times as many coconuts as papayas left. How many coconuts and papayas were there at first?
Answers
Answered by
Anonymous
Let initial amount of coconut and papayas be 5x and 2x.
After 1/2 of coconuts sold.
Coconuts remaining = (1 - 1/2) 5x = 5x/2
After 18 papayas sold, papayas remaining = (2x - 18)
But 2(2x - 18) = 5x/2 (given)
=> 8x - 72 = 5x => x = 24
So Initial amount coconuts = 5x = 120 and papayas = 2x = 48
After 1/2 of coconuts sold.
Coconuts remaining = (1 - 1/2) 5x = 5x/2
After 18 papayas sold, papayas remaining = (2x - 18)
But 2(2x - 18) = 5x/2 (given)
=> 8x - 72 = 5x => x = 24
So Initial amount coconuts = 5x = 120 and papayas = 2x = 48
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