The molar enthalpy of vaporization for water

Question

is 40.79 kJ/mol. Express this enthalpy of
vaporization in joules per gram.
b. The molar enthalpy of fusion for water is
6.009 kJ/mol.How much energy is absorbed when 3.03 g of liquid water boils.

Answer 1

a.
40.79 kJ/mol x (1000 J/kJ) x (1 mol/18.01 g) = ?
b.
Something is missing. I don't understand what the enthalpy of fusion has to do with boiling water. Are you starting with ice? liquid water? what's the temperature of the ice or liquid water. The amout of energy absorbed depends upon what you have initially.