Question

Calculate the molar enthalpy of solidification when 10.00KJ of energy are lost as 30.00g water are frozen at 0*C.

i divided 30/18.02 =1.664 mol
then, divided 10KJ/1.664mol =6.010 KJ/mol

Am i correct?
Thank you!

Answer 1

That looks right to me although I call it latent heat of fusion.