Ask a New Question
Menu

Calculate the molar enthalpy change for this reaction:

HCl(aq 1.00M) + NaOH -> NaCl(aq,.500M)+ H2O

Initial temp: 22.15 degrees Celsius
Extrapolated temp: 25.87 degrees Celsius
DT: 3.72 degrees Celsius

Notes:

Calculate the enthalpy change for this reaction. The density of .500 M Nacl(aq) is 1.02 g/mL and its specific heat capacity is 4.02 J/g degree celsius.

No matter how long I stare at it, and look for videos online, I can not find a definite way to solve this.

2 answers

As I see it you haven't listed a volume; i.e., only mols/L. Without a volume you can't calculate q.
50ml
Similar Questions
  1. HCl(aq) +NaOH(aq) ---> NaCl +H2OIn a coffee cup calorimeter 50 ml of 2.00M HCl was combined with 50ml of 2.05M NaOH. a) What is
    1. answers icon 0 answers
  2. Naoh (aq) + HCl (aq) --> NaCl (aq) + H2O (l)Using the dT determined in part 1, calculate the heat capacity of the calorimeter.
    1. answers icon 2 answers
  3. Naoh (aq) + HCl (aq) --> NaCl (aq) + H2O (l)Using the dT determined in part 1, calculate the heat capacity of the calorimeter.
    1. answers icon 8 answers
    1. answers icon 3 answers
more similar questions