Asked by Tumwesige
A father is now three times as old as his son. In five years the sum of their age will be 58 years. Find their present ages
Answers
Answered by
Tumwesige
Arswer
Answered by
Bosnian
f = father's present ages
s = son's present ages
A father is now three times as old as his son means:
f = 3 s
In five years father will be f + 5 yrs old, son will be s + 5 yrs old.
The sum of their age will be 58 years means:
f + 5 + s + 5 = 58
f + 10 + s = 58
Subtract 10 to both sides
f + s = 48
Replace f by 3 s in this equation
3 s + s = 48
4 s = 48
s = 48 / 4 = 12
f = 3 s = 3 ∙ 12 = 36
Father is now 36 yrs old.
Son is now 12 yrs old.
Check result.
A father is now three times as old as his son:
f / s = 36 / 12 = 3
In five years the sum of their age will be 58 years:
36 + 5 + 12 + 5 = 41 + 17 = 58
s = son's present ages
A father is now three times as old as his son means:
f = 3 s
In five years father will be f + 5 yrs old, son will be s + 5 yrs old.
The sum of their age will be 58 years means:
f + 5 + s + 5 = 58
f + 10 + s = 58
Subtract 10 to both sides
f + s = 48
Replace f by 3 s in this equation
3 s + s = 48
4 s = 48
s = 48 / 4 = 12
f = 3 s = 3 ∙ 12 = 36
Father is now 36 yrs old.
Son is now 12 yrs old.
Check result.
A father is now three times as old as his son:
f / s = 36 / 12 = 3
In five years the sum of their age will be 58 years:
36 + 5 + 12 + 5 = 41 + 17 = 58
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