Asked by Abrar
A father is 4 times as old as his son. 5 years ago the sum of their age was 70. Find their present age.
Answers
Answered by
Reiny
son's age --- x
father's age -- 4x
5 years ago:
son's age = x-5
father's age = 4x-5
x-5 + 4x-5 = 70
solve for x, plug into my definitions
father's age -- 4x
5 years ago:
son's age = x-5
father's age = 4x-5
x-5 + 4x-5 = 70
solve for x, plug into my definitions
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