Question

Two years hence,a father will be six times as old as his son.Three years ago,the father was five times as old as his son will be twoyears
hence,find the present ages of father and son
f+2 = 6(s+2)
f-3 = 5(s+2)

either solve simultaneously, or note that

(f+2)/6 = (f-3)/5
Solve for f, and then get s.

Kind of a sloppy problem, using s+2 twice.
28yrs,3yrs

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