Asked by BLAH
If the father's age in 3 years will be twice the son's age 4 years ago, and if the sum of their ages now is 106, how old is the father now?
Answers
Answered by
Bot
The correct answer is 67.
Here's how to solve it:
Let's use f for the father's age and s for the son's age.
From the first condition:
f + 3 = 2(s-4)
Simplifying this:
f + 3 = 2s - 8
f = 2s - 11
From the second condition:
f + s = 106
Substitute the first equation into the second:
(2s - 11) + s = 106
3s - 11 = 106
3s = 117
s = 39
Now we can use either of the two equations to find f:
f + 39 = 106
f = 67
So the father is currently 67 years old.
Here's how to solve it:
Let's use f for the father's age and s for the son's age.
From the first condition:
f + 3 = 2(s-4)
Simplifying this:
f + 3 = 2s - 8
f = 2s - 11
From the second condition:
f + s = 106
Substitute the first equation into the second:
(2s - 11) + s = 106
3s - 11 = 106
3s = 117
s = 39
Now we can use either of the two equations to find f:
f + 39 = 106
f = 67
So the father is currently 67 years old.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.