Question
Given that x is inversely proportional to y^2. If x=4 when y=3. Find the value of x when y=1
Answers
mathhelper
x is inversely proportional to y^2 ----> x = k(1/y^2)
given: x = 4, when y = 3
4 = k(1/9)
k = 36
so x = 36/y^2
when y = 1,
x = 36/1^1 = 36
given: x = 4, when y = 3
4 = k(1/9)
k = 36
so x = 36/y^2
when y = 1,
x = 36/1^1 = 36