Question

Question 1, Solve for the value of x in the equation 2(1 over g)to power x =32to power (x-3

Question 2, expand (a-2b)(3x+y).

Answer 1

"2(1 over g)to power x =32to power (x-3 "

2(1/g)^x = 32^(x-3)
can't solve since you have 2 variables, but only one equation

I am going to guess that g is supposed to be a 2, so
2(1/2)^x = 32^(x-3)
2^1 * 2^-x = (2^5)^(x-3) = 2^(5x-15)
2(1-x) = 2^(5x-15)
then ...
1 - x = 5x - 15
16 = 6x
x = 8/3



(a-2b)(3x+y)^(x-3)
Just FOIL it
= 3ax + ay - 6bx - 2bx

Answer 2

(2/g)^x= 32^(x-3) perhaps, hard to tell what you mean
but 32 = 2^5
(2/g) = 5(x-3)
I have no idea what your strange text means but perhaps that helps

a(3x+y) -2b(3x+y) { distributive property }
= 3 ax + ay - 6bx - 2by

Answer 3

thanks