Asked by Jake
Acid-Base Titrations
a) How will the concentration of NaOH be affected if during the titration some of the solid potassium hydrogen phthalate was spilled during the transfer? Will the concentration of the standardized NaOH increase, decrease, or have no effect?
b) How will the molar mass of an unknown acid be affected if some of the solid remained after the titration was complete? Will the concentration of the molar increase, decrease, or have no effect?
c) How will the concentration of acetic acid in vinegar be affected if the liquid retained in the pipet is blown out? Will the concentration of acetic acid in vinegar increase, decrease, or have no effect?
d) How will the concentration of acetic acid in vinegar be affected if during the titration an air bubble appears in the tip of the buret? Will the concentration increase, decrease, or have no effect?
a) How will the concentration of NaOH be affected if during the titration some of the solid potassium hydrogen phthalate was spilled during the transfer? Will the concentration of the standardized NaOH increase, decrease, or have no effect?
b) How will the molar mass of an unknown acid be affected if some of the solid remained after the titration was complete? Will the concentration of the molar increase, decrease, or have no effect?
c) How will the concentration of acetic acid in vinegar be affected if the liquid retained in the pipet is blown out? Will the concentration of acetic acid in vinegar increase, decrease, or have no effect?
d) How will the concentration of acetic acid in vinegar be affected if during the titration an air bubble appears in the tip of the buret? Will the concentration increase, decrease, or have no effect?
Answers
Answered by
DrBob222
Look at how you calculated the M of the NaOH.
You had KHP and moles= grams/molar mass.
Then M NaOH = moles/L
So if some of the KHP was spilled, that means grams was too low, which makes moles too low and if moles is too low when plugged into M NaOH, then moles/L will be too low and M will be too low.
The others are done with the same kind of reasoning.
You had KHP and moles= grams/molar mass.
Then M NaOH = moles/L
So if some of the KHP was spilled, that means grams was too low, which makes moles too low and if moles is too low when plugged into M NaOH, then moles/L will be too low and M will be too low.
The others are done with the same kind of reasoning.
Answered by
Confused
KHP?
Answered by
Chris
C and D are worded extremely poor.
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