Asked by Liso

A boy who weighs 200 N is seated 2 m from a fulcrum of a sea saw with another boy who weighs 100 N and is seated 1 m from the fulcrum. How much must a girl sited at 4 m away from a fulcrum on the other side weigh to keep the seasaw at equilibrium.
Answered by Anonymous
200 * 2 + 100 * 1 = w * 4
500 = 4 w
w = 125 Newtons
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