Joe weighs 30 lbs less than twice ken's weight. If ken gains 10 pounds then together they would weigh 250 pounds. How much does each of them weigh? let x be ken's weight.

Question

thanks

Answer 1

Joe weighs 30lbs less than 2wice kens weight
J=2x-30

ken gains 10lbs, then 2gether would weigh 250
(x+10)+J = 250

J=joe's weight.

solve them simultaneously..

hope that helps

Answer 2

im confused can you explain a little more cause i need a full equation and im really confused

Answer 3

you need to construct simultaneous equations from the information;

first equation is from; Joe weighs 30lbs less than 2wice kens weight. and x is ken's weight. so twice kens weight is 2x. 30lbs less than twice kens weight is 2x-30. these equals to Joes weight
J=2x-30 (1)

we cannot work with this equation alone because, there are two unknowns J and x. so we need another equation which is obtained from; If ken gains 10 pounds then together they would weigh 250 pounds.

i.e. if ken gains 10lbs (x+10), then together (with J) will equal to 250.
(x+10)+J = 250 (2)

Now we can solve for each weight either by substitution or elimination method..