Question
A long-distance runner runs 6 miles directly south and then faces due east and runs another 10 miles. How far is the runner, in a straight line, from his starting point?
Answers
just a right-angled triangle, so Pythagoras
L^2 = 6^2 + 10^2
= 136
L = √136 = ....
L^2 = 6^2 + 10^2
= 136
L = √136 = ....
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