Asked by Grace
                The area of a triangle is growing at a rate of 4 cm2/min. If the height of this triangle is always twice the base, find the rate of change of the base when the base is 6cm.
            
            
        Answers
                    Answered by
            mathhelper
            
    let the base be x cm
then the height is 2x cm
Area = (1/2)(base)(height)
= (1/2)(x)(2x) = x^2
d(Area)/dt = 2x dx/dt
given: d(area)/dt = 4 cm^2 / min
find : dx/dt when x = 6 cm
4 = 2(6) dx/dt
dx/dt = 1/3 cm/min
    
then the height is 2x cm
Area = (1/2)(base)(height)
= (1/2)(x)(2x) = x^2
d(Area)/dt = 2x dx/dt
given: d(area)/dt = 4 cm^2 / min
find : dx/dt when x = 6 cm
4 = 2(6) dx/dt
dx/dt = 1/3 cm/min
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