Asked by Grace

The area of ​​a triangle is growing at a rate of 4 cm2/min. If the height of this triangle is always twice the base, find the rate of change of the base when the base is 6cm.

Answers

Answered by mathhelper
let the base be x cm
then the height is 2x cm

Area = (1/2)(base)(height)
= (1/2)(x)(2x) = x^2
d(Area)/dt = 2x dx/dt

given: d(area)/dt = 4 cm^2 / min
find : dx/dt when x = 6 cm

4 = 2(6) dx/dt
dx/dt = 1/3 cm/min

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