Include an explanation, balanced chemical equation, units, significant figures and/or calculations where appropriate.
Standardization of NaOH Solution
Trial 1:
0.501 g KHC8H4O4
15.22 mL NaOH
Trial 2:
0.503 g KHC8H4O4
15.11 mL
Trial 3:
0.500 g KHC8H4O4
15.10 mL
Using the data presented above, calculate the concentration of your standard sodium hydroxide solution. Include the calculation for each trial and the average.
5 answers
Are you asking me to do your homework? or your lab work? Tell me what you don't understand and I can help you through it.
I'm not sure how to start it.
I know I need to have a balanced chemical equation, so...
KHC8H4O4 (aq) + NaOH (aq) --> H2O (l) + ????
Then once I figure this out, do I use the mass in each trial to find the moles of NaOH through stoichiometry.
Then divide the number of moles by the volume of NaOH.
??
I know I need to have a balanced chemical equation, so...
KHC8H4O4 (aq) + NaOH (aq) --> H2O (l) + ????
Then once I figure this out, do I use the mass in each trial to find the moles of NaOH through stoichiometry.
Then divide the number of moles by the volume of NaOH.
??
Simplify the KHC8H4O4 to KHT.
Then KHT + NaOH ==> NaKT + HOH
mols KHT = grams/molar mass
mols HHT = moles NaOH.
M NaOH = moles/L NaOH.
You will have a M for each trial, then average the values you obtain.
Then KHT + NaOH ==> NaKT + HOH
mols KHT = grams/molar mass
mols HHT = moles NaOH.
M NaOH = moles/L NaOH.
You will have a M for each trial, then average the values you obtain.
Theory background of standardizing NaOH with KHP
What’s the concentration of the NaOH solution was found to be exactly??
3 answers