Asked by trump
What volume of a 15.0% by mass NaOH solution, which has a density of 1.116 g/mL, should be used to make 4.95 L of an NaOH solution with a pH of 10.4?
Express your answer to three significant figures and include the appropriate units.
Express your answer to three significant figures and include the appropriate units.
Answers
Answered by
DrBob222
First step: Determine the molarity of the 15.0% NaOH solution. It is
1.116 g/mL x 1000 mL x 0.15 x (1/40) = about 4 M but that's just an estimate. You calculate it and use your number, not mine.
Then mL1 x M1 = mL2 x M2
L1 = ?
M1 = 4 or whatever you obtained in your calculation.
L2 = 4.95 from the problem
M2 = Convert pH to pOH (pH + pOH = 14) and convert pOH to OH^- by pOH = -log(OH^-)
Post your work if you get stuck.
1.116 g/mL x 1000 mL x 0.15 x (1/40) = about 4 M but that's just an estimate. You calculate it and use your number, not mine.
Then mL1 x M1 = mL2 x M2
L1 = ?
M1 = 4 or whatever you obtained in your calculation.
L2 = 4.95 from the problem
M2 = Convert pH to pOH (pH + pOH = 14) and convert pOH to OH^- by pOH = -log(OH^-)
Post your work if you get stuck.
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