Asked by Anonymous
A store owner has 130 more oranges than soursops. After he sold 80% of the oranges and 30% of the soursops, he is left 19 more soursops than oranges. What fraction of the fruits left were soursops?
Answers
Answered by
Anonymous
Let the number of soursops be x.
Before sold:
orange: x + 130
soursops: x
After sold:
(1 - 30%)x - (1 - 80%) (x + 130) = 19
0.7x - 0.2x - 26 = 19
0.5x = 45
x = 90
Left: orange:
(1 - 80%) (x + 130)
= 0.2 * 220 = 44
soursop: (1 - 30%)x = 0.7 * 90 = 63
63/(44 + 63) = 63/107
The fractions is 63/107.
Before sold:
orange: x + 130
soursops: x
After sold:
(1 - 30%)x - (1 - 80%) (x + 130) = 19
0.7x - 0.2x - 26 = 19
0.5x = 45
x = 90
Left: orange:
(1 - 80%) (x + 130)
= 0.2 * 220 = 44
soursop: (1 - 30%)x = 0.7 * 90 = 63
63/(44 + 63) = 63/107
The fractions is 63/107.
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