Question
John filled 3/8 of a tank with 3 identical jugs of water. He poured another 2 identical jugs and 9 identical cups of water to fill the tank to its brim.
(a) What fraction of the tank can 1 jug of water fill?
(b) If only cups are used to fill the empty tank to its brim, how many
identical cups are needed?
(a) What fraction of the tank can 1 jug of water fill?
(b) If only cups are used to fill the empty tank to its brim, how many
identical cups are needed?
Answers
Anonymous
3 identical jugs can fill 3/8 pour of a tank.
fraction of the tank filled by one jug = 3/8 / 3 = 1/8
Total number of jugs required = 3 + 2 = 5
Parts filled = 5/8
Remaining part = 1/1 - 5/8 = 3/8
9 cup fill 3/8 part
1 cup will fill, 3/8 / 9 pour
= 1/24
So, no. of cup required to fill the entire tank = 1 / 1/24 = 1 * 24 = 24
(a) 1/8 (b) 24
fraction of the tank filled by one jug = 3/8 / 3 = 1/8
Total number of jugs required = 3 + 2 = 5
Parts filled = 5/8
Remaining part = 1/1 - 5/8 = 3/8
9 cup fill 3/8 part
1 cup will fill, 3/8 / 9 pour
= 1/24
So, no. of cup required to fill the entire tank = 1 / 1/24 = 1 * 24 = 24
(a) 1/8 (b) 24
mathhelper
let capacity of tank be t
3j = 3t/8
j = t/8 ----> one jug fills 1/8 of the tank
t = 8j
2j + 9c = t
2j + 9c = 8j
9c = 6j = 6(t/8) = (3/4)t
36/3 = t
t = 12
it would take 12 cups to fill the tank
3j = 3t/8
j = t/8 ----> one jug fills 1/8 of the tank
t = 8j
2j + 9c = t
2j + 9c = 8j
9c = 6j = 6(t/8) = (3/4)t
36/3 = t
t = 12
it would take 12 cups to fill the tank