Asked by Jake
How much applied force is needed to accelerate a 2.0 kg block of wood from rest to 8.0 m/s [F] in
2.0 s along a rough table surface which results in a frictional force of 10.0 N.
2.0 s along a rough table surface which results in a frictional force of 10.0 N.
Answers
Answered by
R_scott
f = m a = 2.0 kg * (8.0 / 2.0) m/s^2 = 8.0 N
the frictional force should be added to the required accelerating force
necessary applied force = ?
the frictional force should be added to the required accelerating force
necessary applied force = ?