Question
A 12N force is applied to a 20kg door If a frictional torque is present what will be the angular acceleration of the door The door is 80cm wide and I=1/3ml^2.
Answers
bobpursley
torque= I*angacc
12*.8=1/3 m (.8^2)*angacceleration
12*.8=1/3 m (.8^2)*angacceleration
ami
A 12N force is applied to a 20kg door If a 5m.N frictional torque is present what will be the angular acceleration of the door The door is 80cm wide and I=1/3ml^2.
bobpursley
you are correct, I did not subtract frictional torque.
12*.8-.5= .....
12*.8-.5= .....