Asked by ami

A 12N force is applied to a 20kg door If a frictional torque is present what will be the angular acceleration of the door The door is 80cm wide and I=1/3ml^2.
Answered by bobpursley
torque= I*angacc

12*.8=1/3 m (.8^2)*angacceleration
Answered by ami
A 12N force is applied to a 20kg door If a 5m.N frictional torque is present what will be the angular acceleration of the door The door is 80cm wide and I=1/3ml^2.
Answered by bobpursley
you are correct, I did not subtract frictional torque.

12*.8-.5= .....
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