Asked by anon
How to calculate the atoms of each element in Fe2 (SO4)3?
And an explanation on how to calculate for other formulas.
And an explanation on how to calculate for other formulas.
Answers
Answered by
oobleck
SO4 has 5 atoms
so (SO4)3 has 5*3 = 15 atoms
Now just add the 2 Fe atoms, and you have 17 atoms per molecule
2 Fe
3*1 = 3 S
3*4 = 12 O
so (SO4)3 has 5*3 = 15 atoms
Now just add the 2 Fe atoms, and you have 17 atoms per molecule
2 Fe
3*1 = 3 S
3*4 = 12 O
Answered by
DrBob222
You can't get a better answer than oobleck gave you for Fe2(SO4)3.
Here is how you do ANY formula. For example, 2Mg(ClO3)2.
The number AFTER the element multiplies just that element; i.e., Mg is 1, Cl is 1, O is 3. The number AFTER a set of parentheses multiplies everything within the parentheses; i.e., Cl is 2, O is 6. A number BEFORE the formula multiplies everything that follows by that number; i.e., Mg is 2 (2*1), Cl is 4 (2*2) and O is 12 (2*6).
Here is how you do ANY formula. For example, 2Mg(ClO3)2.
The number AFTER the element multiplies just that element; i.e., Mg is 1, Cl is 1, O is 3. The number AFTER a set of parentheses multiplies everything within the parentheses; i.e., Cl is 2, O is 6. A number BEFORE the formula multiplies everything that follows by that number; i.e., Mg is 2 (2*1), Cl is 4 (2*2) and O is 12 (2*6).
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