Asked by help me pls
The position of a leaf as it floats along a river is given by the function s(x) = x^3 - sinx, where s(x) is in meters and x is time in seconds.
- Find the acceleration of the leaf at 2pi seconds.
- Is the leaf moving in its original direction or in the opposite direction that it was originally moving?
Leave all solutions in exact form.
(please show the steps if you can, so i can follow)
- Find the acceleration of the leaf at 2pi seconds.
- Is the leaf moving in its original direction or in the opposite direction that it was originally moving?
Leave all solutions in exact form.
(please show the steps if you can, so i can follow)
Answers
Answered by
mathhelper
"The position of a leaf " , relative to what ?
anyway ....
s(x) = x^3 - sinx
v(x) = 3x^2 - cosx
a(x) = 6x + sinx
so when x = 2π
a(2π) = 12π + sin(2π) = 12π + 0 = 12π
anyway ....
s(x) = x^3 - sinx
v(x) = 3x^2 - cosx
a(x) = 6x + sinx
so when x = 2π
a(2π) = 12π + sin(2π) = 12π + 0 = 12π
Answered by
oobleck
v(0) = -1 < 0
v(2π) = 12π^2 - 1 > 0
so it is now moving in the opposite direction
v(2π) = 12π^2 - 1 > 0
so it is now moving in the opposite direction
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