Asked by help me pls
Calculate the derivatives of the following:
(also please could you show the steps, i'm so confused)
a) y = sinx - cosx
b) f(x) = x^2 + cosx
c) y = sin(x^2)
d) f(x) = x^5 sin (2x^3)
e) y = cos (sinx)
f) f(x) = sin^2 x
(also please could you show the steps, i'm so confused)
a) y = sinx - cosx
b) f(x) = x^2 + cosx
c) y = sin(x^2)
d) f(x) = x^5 sin (2x^3)
e) y = cos (sinx)
f) f(x) = sin^2 x
Answers
Answered by
mathhelper
a) y = sinx - cosx
b) f(x) = x^2 + cosx <---- you absolutely must know how to do this
c) y = sin(x^2) <---- you absolutely must know how to do this
d) f(x) = x^5 sin (2x^3) <--- product rule
firstline derivative:
f ' (x) = (5x^4)sin(2x^3) + 4x^4(6x^2)cos(2x^3)
= ....
e) y = cos (sinx)
dy/dx = -sin(sinx) ( cosx)
did you mean: y = (cosx)(sinx) ?? , that would need a simple product rule
f) f(x) = sin^2 x or (sinx)^2 <---- you absolutely must know how to do this
b) f(x) = x^2 + cosx <---- you absolutely must know how to do this
c) y = sin(x^2) <---- you absolutely must know how to do this
d) f(x) = x^5 sin (2x^3) <--- product rule
firstline derivative:
f ' (x) = (5x^4)sin(2x^3) + 4x^4(6x^2)cos(2x^3)
= ....
e) y = cos (sinx)
dy/dx = -sin(sinx) ( cosx)
did you mean: y = (cosx)(sinx) ?? , that would need a simple product rule
f) f(x) = sin^2 x or (sinx)^2 <---- you absolutely must know how to do this
Answered by
oobleck
d) f(x) = x^5 sin (2x^3) <--- product rule and chain rule
f ' (x) = (5x^4)sin(2x^3) + x^5(6x^2)cos(2x^3)
f ' (x) = (5x^4)sin(2x^3) + x^5(6x^2)cos(2x^3)
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