Asked by Anonymous
Jessa, Tessa and Titus shared some cookies. Jessa took 6 more than 1/4 of the cookies. Tessa took 2 more than 2/3 of the rest of the cookies. Titus took the last 12 cookies. How many cookies did Tessa take?
Answers
Answered by
Anonymous
Let the number of cookies be x.
=> Jessa => x/4 + 6
cookies left = x - (x/4 + 6)
= x/1 - x/4 - 6
= (4x - x)/4 + 6
= 3x/4 + 6
=> Tessa =>
2 + 2/3 (3x/4 + 6)
=> Titus => 12
(x/4 + 16) + (2 + 2/3 (3x/4 + 6)) + 12 = x
x/4 + 6 + 2 + 6/12x + 12/3 + 12 = x
x/4 + x/12 + 20/1 + 12/3 = x
x/4 + x/2 + (60 + 12)/3 = x
(x + 2x)/4 + 72/3 = x
3x/4 + 24 = x
24 = x - 3x/4
24 = x/4
x = 24 * 4 = 96
Tessa took
2 + 2/3 (3/4(96) + 6)
2 + 2/3 (72 + 6)
2 + 52
54 cookies
=> Jessa => x/4 + 6
cookies left = x - (x/4 + 6)
= x/1 - x/4 - 6
= (4x - x)/4 + 6
= 3x/4 + 6
=> Tessa =>
2 + 2/3 (3x/4 + 6)
=> Titus => 12
(x/4 + 16) + (2 + 2/3 (3x/4 + 6)) + 12 = x
x/4 + 6 + 2 + 6/12x + 12/3 + 12 = x
x/4 + x/12 + 20/1 + 12/3 = x
x/4 + x/2 + (60 + 12)/3 = x
(x + 2x)/4 + 72/3 = x
3x/4 + 24 = x
24 = x - 3x/4
24 = x/4
x = 24 * 4 = 96
Tessa took
2 + 2/3 (3/4(96) + 6)
2 + 2/3 (72 + 6)
2 + 52
54 cookies
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