Question

A motorist speeding at 54km/h from town A to town B and back at a speed of 72km/h takes 8.75 hours.How far is town B from town A?
Time for first trip = d/54
time for 2nd trip = d/72, where d is the distance between the towns

d/54 + d/72 = 8.75

times 216 , the LCD
4d + 3d = 1890
d = 1890/7 km = ...

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