Asked by p00pjoke
hi can anyone explain how to do this? im stumped.
4r-4/r^2 + 5r-24 + 4/r+8 = 3/r-3
4r-4/r^2 + 5r-24 + 4/r+8 = 3/r-3
Answers
Answered by
Anonymous
I have a sneaking suspicion that you need some parentheses.
Answered by
oobleck
I'll guess you meant
(4r-4)/(r^2 + 5r-24) + 4/(r+8) = 3/(r-3)
(4r-4)/((r+8)(r-3)) + 4/(r+8) = 3/(r-3)
(4r-4 + 4(r-3))/((r+8)(r-3)) = 3(r+8)/((r+8)(r-3))
4r-4+4r-12 = 3r+24
8r-16 = 3r+24
5r = 40
r = 8
(4r-4)/(r^2 + 5r-24) + 4/(r+8) = 3/(r-3)
(4r-4)/((r+8)(r-3)) + 4/(r+8) = 3/(r-3)
(4r-4 + 4(r-3))/((r+8)(r-3)) = 3(r+8)/((r+8)(r-3))
4r-4+4r-12 = 3r+24
8r-16 = 3r+24
5r = 40
r = 8
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