Question

Suppose the number of cell phones in a household has a binomial distribution with parameters n=24 and p=25%.

Find the probability of a household having:
(a) 11 or 16 cell phones

(b) 14 or fewer cell phones

(c) 18 or more cell phones

(d) fewer than 16 cell phones

(e) more than 14 cell phones

Answer 1

same type of question as the previous one, except even more
tedious button pushing.

e.g.
c) 18 or more
= C(24,18) (.25^18) (.75^6) + C(24,19)(.25^19)(.75^5) + ....
.... + C(24,24)(.25^24)(.75^0)
= ....

good grief!, hope you have a good calculator