Asked by Jess
Suppose the number of cell phones in a household has a binomial distribution with parameters n=24 and p=25%.
Find the probability of a household having:
(a) 11 or 16 cell phones
(b) 14 or fewer cell phones
(c) 18 or more cell phones
(d) fewer than 16 cell phones
(e) more than 14 cell phones
Find the probability of a household having:
(a) 11 or 16 cell phones
(b) 14 or fewer cell phones
(c) 18 or more cell phones
(d) fewer than 16 cell phones
(e) more than 14 cell phones
Answers
Answered by
mathhelper
same type of question as the previous one, except even more
tedious button pushing.
e.g.
c) 18 or more
= C(24,18) (.25^18) (.75^6) + C(24,19)(.25^19)(.75^5) + ....
.... + C(24,24)(.25^24)(.75^0)
= ....
good grief!, hope you have a good calculator
tedious button pushing.
e.g.
c) 18 or more
= C(24,18) (.25^18) (.75^6) + C(24,19)(.25^19)(.75^5) + ....
.... + C(24,24)(.25^24)(.75^0)
= ....
good grief!, hope you have a good calculator