Question
At 500 °C, hydrogen iodide decomposes according to
2HI(g)↽−−⇀H2(g)+I2(g)
For HI(g) heated to 500 °C in a 1.00 L reaction vessel, chemical analysis determined these concentrations at equilibrium: [H2]=0.359 M , [I2]=0.359 M , and [HI]=3.03 M . If an additional 1.00 mol of HI(g) is introduced into the reaction vessel, what are the equilibrium concentrations after the new equilibrium has been reached?
[HI]=
M
[H2]=
M
[I2]=
M
2HI(g)↽−−⇀H2(g)+I2(g)
For HI(g) heated to 500 °C in a 1.00 L reaction vessel, chemical analysis determined these concentrations at equilibrium: [H2]=0.359 M , [I2]=0.359 M , and [HI]=3.03 M . If an additional 1.00 mol of HI(g) is introduced into the reaction vessel, what are the equilibrium concentrations after the new equilibrium has been reached?
[HI]=
M
[H2]=
M
[I2]=
M
Answers
Related Questions
Ammonium iodide dissociates reversibly to ammonia and hydrogen iodide:
NH4I(s) ↔ NH3(g) + HI(g)
At...
Ammonium iodide dissociates reversibly to ammonia and hydrogen iodide.
NH4I(s) Picture NH3(g) +...
2. Solid ammonium iodide decomposes to yield ammonia gas(NH3) and hydrogen iodide gas at 400oF. The...