Asked by Aayu Patel
Suppose f(pi/6) = 7 and f’(pi/6) = 2
and let g(x) = f(x)cosx and h(x) = sinx/f(x)
g’(pi/6)=
h’(pi/6)=
and let g(x) = f(x)cosx and h(x) = sinx/f(x)
g’(pi/6)=
h’(pi/6)=
Answers
Answered by
oobleck
g' = f' cosx - f sinx
h' = (f' sinx - f cosx)/f^2
so plug in your numbers. Post your work if you get stuck
h' = (f' sinx - f cosx)/f^2
so plug in your numbers. Post your work if you get stuck
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