Asked by Wealth
If 4÷3,m,1,n form a Gp what is the product of m and n
Answers
Answered by
PsyDAG
It would help if you would proofread your work before you post it.
Clarify your post.
Clarify your post.
Answered by
mathhelper
So your terms of the GP are
4/3, m, 1, n
so a = 4/3
m = ar = (4/3)r
1 = ar^2 ----> 1 = 4/3 r^2
r^2 = 3/4
r = ± √3/2
then n = ar^3 = (4/3)(±√3/2)^3 = ± √3/2
m = ar = (4/3)(±√3/2) = ±√3
check:
4/3, √3, 1, √3/2 do form a GP, so does
4/3, -√3, 1, -√3
4/3, m, 1, n
so a = 4/3
m = ar = (4/3)r
1 = ar^2 ----> 1 = 4/3 r^2
r^2 = 3/4
r = ± √3/2
then n = ar^3 = (4/3)(±√3/2)^3 = ± √3/2
m = ar = (4/3)(±√3/2) = ±√3
check:
4/3, √3, 1, √3/2 do form a GP, so does
4/3, -√3, 1, -√3
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.