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If a solution of chloride in water is 0.354 M Cl− at 25°C,
and the density of the solution 0.456 g/mL, what is the
molality of Cl− in the solution?
3 years ago

Answers

DrBob222
0.354 M = 0.354 mols Cl^-/ L solution.
If the density of the solution is 0.456 g/mL then the solution has a mass of
mass = volume x density = 1000 mL x 0.456 g/mL = 456 g or 0.456 kg.
molality = mols/kg solvent; therefore, molality = m = 0.354/0.456 = ?
3 years ago

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