Asked by Anonymous
given that y= root x +k/x and that dy/dx = 2 when x=4 find the value of the constant k
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Answered by
Anonymous
y = x^.5 + k x^-1 ???
dy/dx = .5 x^-.5 -k x^-2
2 = .5 /2 - k /16
4 = .5 - k/8
dy/dx = .5 x^-.5 -k x^-2
2 = .5 /2 - k /16
4 = .5 - k/8
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