Asked by Emma
What volume of 3M hydrochloric acid will be required to react completely with 3.25 g of zinc
Answers
Answered by
Emma
Now
Answered by
oobleck
impatient much?
how many moles of Zn in 3.25g?
The equation will tell you how many moles of HCl will be used
3M HCl = 3 moles/liter, so divide the moles HCl by 3 to get liters
how many moles of Zn in 3.25g?
The equation will tell you how many moles of HCl will be used
3M HCl = 3 moles/liter, so divide the moles HCl by 3 to get liters
Answered by
DrBob222
Zn + 2HCl ==> ZnCl2 + H2
mols Zn = grams/atomic mass = 3.25/65.4 = about 0.0496 but you need to confirm the atomic mass Zn and give a more accurate answer.
Then from the equation, that many mols Zn will require twice that many mols of HCl.
Finally, mols = M HCl x L HCl. You know mols HCl and M HCl, solve for L HCl. Convert to mL if desired.
Post your work if you get stuck.
mols Zn = grams/atomic mass = 3.25/65.4 = about 0.0496 but you need to confirm the atomic mass Zn and give a more accurate answer.
Then from the equation, that many mols Zn will require twice that many mols of HCl.
Finally, mols = M HCl x L HCl. You know mols HCl and M HCl, solve for L HCl. Convert to mL if desired.
Post your work if you get stuck.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.