Asked by Desa
                The length of latus rectum of an ellipse x²+ 4y²= 8
            
            
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                    Answered by
            Desa
            
    What is the length of latus rectum of an ellipse  x² + 4y² =8 
    
                    Answered by
            Desa
            
     Find equation of parabola  x² + 4x+y=0
    
                    Answered by
            mathhelper
            
    By definition:
For x^2/a^2 + y^2/b^2 = 1, the length of the latus rectum is 2b^2/a
for x^2 + 4y^2 = 8
x^2/8 + y^2/2 = 1
so a^2 = 8, and b^2 = 2, thus a = √8 = 2√2
length of LR = 2(2)/(2√2) = 2/√2 = √2
    
For x^2/a^2 + y^2/b^2 = 1, the length of the latus rectum is 2b^2/a
for x^2 + 4y^2 = 8
x^2/8 + y^2/2 = 1
so a^2 = 8, and b^2 = 2, thus a = √8 = 2√2
length of LR = 2(2)/(2√2) = 2/√2 = √2
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