Asked by jeon selin
Given: diameter of the atomic nucleus of a lead atom is 1.75 × 10-15 m. What is its nucleus volume?
Answers
Answered by
mathhelper
Just using
V = (4/3)π r^3
= (4/3)π(1.75 x 10^-15)^3
= (4/3)π(5.359375)(10)^-45
= 22.449 x 10^-45
= 2.2449 x 10^-44 m^3
V = (4/3)π r^3
= (4/3)π(1.75 x 10^-15)^3
= (4/3)π(5.359375)(10)^-45
= 22.449 x 10^-45
= 2.2449 x 10^-44 m^3
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