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The volume of water in a container is x(2x²+x+5)cm³ when the depth is Xcm water is added at the rate of 60cm³5¯¹ when the depth...Asked by Apakhade
The volume of water in a container is x(2x^2 + x + 5)cm^3 when the depth is xcm. Water is added at a constant rate of 60cm^3/s when the depth is 5cm, at what rate is the level rising?
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Answered by
oobleck
v = 2x^3 + x^2 + 5x
dv/dt = (6x^2 + 2x + 5) dx/dt
when x=5,
60 = 165 dx/dt
so dx/dt = 4/11 cm/s
dv/dt = (6x^2 + 2x + 5) dx/dt
when x=5,
60 = 165 dx/dt
so dx/dt = 4/11 cm/s
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