take oneliter of the HNO3.
weight=1500grams
massHNO3=.63*1500
Molarity HNO3=.63*1500/63*1=15
Now you want to dilute it 15 times to get a 1 molar solution. That means one part HNO3 stock, 14 parts water.
if the one part is 50ml, then water is 14*50=700ml, or .7 liter.
What volume of water should be added to 50 ml of HNO3 having specific gravity 1.5g ml-1 and 63.0%by weight to have one molar solution
2 answers
dont know