Asked by Anonymous
The number of cakes brought each year in Illinois from 1990 to 2015 can be approximated by w(t)=412e^(0.071t) (0≥t≤25) with t being the time in years since the start of 1990. How exactly do I find ∫ (with 25 as upper limit and 5 as lower) w(t) dt.
Answers
Answered by
oobleck
since ∫e^(at) = 1/a e^(at), you have
∫[5,25] 412e^(0.071t) dt = 412/0.071 e^(0.071t) [5,25]
= 5802.82(e^(.071*25) - e^(.071*5))
= 25962.40
∫[5,25] 412e^(0.071t) dt = 412/0.071 e^(0.071t) [5,25]
= 5802.82(e^(.071*25) - e^(.071*5))
= 25962.40
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