Question
What is the molarity of 125ml of hydrochloric acid (HCl) needed to neutralize 5 Liters (5L) of 10M sodium hydroxide?
Answers
HCl + NaOH ==> NaCl + H2O
mols NaOH = molarity x liters = M x L = 10 M x 5 L = 50 moles.
From the equation 1 mol HCl neutralizes 1 mol NaOH; therefore, you need 50 mols HCl. For HCl moles = M x L. You know L = 0.125 and moles = 50. Solve for M.
mols NaOH = molarity x liters = M x L = 10 M x 5 L = 50 moles.
From the equation 1 mol HCl neutralizes 1 mol NaOH; therefore, you need 50 mols HCl. For HCl moles = M x L. You know L = 0.125 and moles = 50. Solve for M.
Related Questions
How many grams of CH3COOH are needed to make 4.2 liters of aqueous solution of pH=3.4?Be sure to bac...
How many liters of 80% hydrochloric acid must be mixed with 40% hydrochloric acid to get 15 liters o...
If 34.3 mL of barium hydroxide are required to neutralize 15.9 mL of the acid, what is the molarity...
In a titration, 54.5 mL of 0.6 M hydrochloric acid solution is needed to neutralize 78 mL of potassi...