Asked by Help please
If x is in quadrant I and sinx-cosx=1/3, then the value of sinx+cosx is…
A)4/3 B)sqrt17/3 C)-4/9
A)4/3 B)sqrt17/3 C)-4/9
Answers
Answered by
oobleck
(sinx-cosx)^2 = 1 - 2sinx cosx = 1/9
so sin2x = 8/9
(sinx-cosx)(sinx+cosx) = sin^2x - cos^2x = -cos2x
cos^2(2x) = 1 - 64/81 = 17/81
sinx+cosx = (√17/9)/(1/3) = √17/3
so sin2x = 8/9
(sinx-cosx)(sinx+cosx) = sin^2x - cos^2x = -cos2x
cos^2(2x) = 1 - 64/81 = 17/81
sinx+cosx = (√17/9)/(1/3) = √17/3
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