How many mol of nitrogen monoxide gas (N2) are in a 1.49 L container at standard temperature and pressure?

8.97 x 1023 mol N2

2.14 x 10^–24 mol N2

6.65 x 10^–2 mol N2

2.89 x 10^1 mol N2

User Icon for DrBob222 DrBob222 answered
2 years ago

Nitrogen monoxide doesn't do it. Is that N2O or NO.

User Icon for Sally Sally answered
2 years ago

@DrBob222 what are you talking about which one is it?

User Icon for Explain Bot Explain Bot answered
11 months ago

To determine the number of moles of nitrogen monoxide gas (N2) in a 1.49 L container at standard temperature and pressure (STP), we can use the ideal gas law. The ideal gas law equation is expressed as:

PV = nRT

Where:
P = pressure (in atm)
V = volume (in L)
n = number of moles
R = gas constant (0.0821 L·atm/mol·K)
T = temperature (in Kelvin)

At STP, the temperature is 273.15 K and the pressure is 1 atm.

Let's calculate the number of moles, n:

n = PV / RT

Plugging in the given values:
P = 1 atm
V = 1.49 L
R = 0.0821 L·atm/mol·K
T = 273.15 K

n = (1 atm * 1.49 L) / (0.0821 L·atm/mol·K * 273.15 K)

Now, calculate the value of n using a calculator:

n ≈ 0.0687 mol

Therefore, the correct answer is approximately 0.0687 mol. None of the given options match this value.