Asked by Avela
Given the first three terms of the arithmetic sequence
(2p-3) ; (p-5);(2p+7)
find the value of p
(2p-3) ; (p-5);(2p+7)
find the value of p
Answers
Answered by
mathhelper
by definition of AP
p-5 - (2p-3) = 2p+7 - (p-5)
p - 5 - 2p + 3 = 2p + 7 - p + 5
I will let you solve this for p, very straight forward.
p-5 - (2p-3) = 2p+7 - (p-5)
p - 5 - 2p + 3 = 2p + 7 - p + 5
I will let you solve this for p, very straight forward.
Answered by
Avela
Struggling to find the answer
Answered by
mathhelper
from:
p - 5 - 2p + 3 = 2p + 7 - p + 5
-p - 2 = p + 12
-2p = 14
p = -7
p - 5 - 2p + 3 = 2p + 7 - p + 5
-p - 2 = p + 12
-2p = 14
p = -7
Answered by
oobleck
you forget your Algebra I?
p - 5 - 2p + 3 = 2p + 7 - p + 5
-p-2 = p+12
-2p = 14
p = -7
p - 5 - 2p + 3 = 2p + 7 - p + 5
-p-2 = p+12
-2p = 14
p = -7
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