the vapour pressure of ethanol (C2H5OH)and 1-propanol(C3H7OH)at35c are 100mmHg and 37.6mmHg,respectively.assuming ideal behaviour,calculate the partial vapour pressures of ethanol and 1-propanol over a solution ,in which the mole fraction of ethanol is 0.3.
3 answers
yes
answer question
Pethanol = Xethanol*Poethanol
Pethanol = 0.3*100 = ?
Mole fractions always add to 1.0; therefore, mole fraction 1-propanol = 0.7, then P1-propanol = Xpropanol*Popropanol
Post your work if you get stuck.
Pethanol = 0.3*100 = ?
Mole fractions always add to 1.0; therefore, mole fraction 1-propanol = 0.7, then P1-propanol = Xpropanol*Popropanol
Post your work if you get stuck.